Velocity from Displacement (Exponential) – Rankers Physics
Topic: Kinematics
Subtopic: Calculus Based Questions

Velocity from Displacement (Exponential)

The displacement \( x \) of a particle varies with time \( t \) as \( x = ae^{-\alpha t} + be^{\beta t} \), where \( a, b, alpha \) and \( beta \) are positive constants. The velocity of the particle will

(2005)

Be independent of \( \beta \)
Drop to zero when \( \alpha = \beta \)
Go on decreasing with time
Go on increasing with time

Solution:

Concept: Velocity is the time derivative of displacement. Calculate \( v = \frac{dx}{dt} = -a\alpha e^{-\alpha t} + b\beta e^{\beta t} \). The term \( -a\alpha e^{-\alpha t} \) decreases in magnitude (approaching zero), while the term \( b\beta e^{\beta t} \) increases exponentially. Thus, the velocity of the particle will go on increasing with time.

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