[2019]
Solution:
Assuming a common typo in the question and the formula should be \(X = \frac{A^2 B^{1/2}}{CD}): Percentage error in \(X = 2(\Delta A/A) + (1/2)(\Delta B/B) + (\Delta C/C) + (\Delta D/D)\). This gives \(2(1%) + (1/2)(2%) + 1(3%) + 1(4%) = 2% + 1% + 3% + 4% = 10%\).
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